Question

3x÷(x^3-1)-5÷(4x^2+4x+14)=1÷(2(1-x))

Answer 1

Привет!!! ^ это умножить???

Answer 2

To solve the equation 3x÷(x^3-1)-5÷(4x^2+4x+14)=1÷(2(1-x)), we'll follow a step-by-step approach:

Step 1: Simplify the equation by getting rid of the fractions. To do this, we'll find the common denominator and multiply every term by it.

The common denominator for the fractions is (x^3 - 1) * (4x^2 + 4x + 14) * 2(1 - x). Multiplying every term by this common denominator, we get:

3x * (4x^2 + 4x + 14) * 2(1 - x) - 5 * (x^3 - 1) * 2(1 - x) = (x^3 - 1) * (4x^2 + 4x + 14)

Simplifying further:

24x^2 - 24x^3 - 12x + 12x^2 + 60x - 60 + 10x^3 - 10x = 4x^5 + 4x^4 + 14x^3 + 4x^2 + 14x + 56x^2 + 56x + 196

Step 2: Combine like terms on both sides of the equation.

-14x^5 - 6x^4 + 20x^3 + 98x^2 + 98x + 196 = 0

Step 3: Rearrange the equation to bring all terms to one side.

14x^5 + 6x^4 - 20x^3 - 98x^2 - 98x - 196 = 0

Step 4: Factor the equation if possible. However, factoring a quintic equation (degree 5) is generally difficult and might not have a simple factorization.

Unfortunately, the given equation doesn't seem to have a simple factorization, and solving it analytically may be quite complex. In such cases, numerical methods or approximation techniques, like graphing or iterative methods, can be used to find the solutions.