Question

F(x)=1/3x^3-1/2x^2-2x+1 x0=1

Answer 1

Ответ:

Пошаговое объяснение:

Найдем производную функции

F'(x)= (1/3x^3+4x^2-2x+1)' = (1/3x^3)'+(4x^2)'-(2x)'+1' =  \\  \\ = x^2+8x-2

Найдем значение в точке х0

F'(x_0)= F'(3) = 3^2+8*3-2 = 31

Ответ:

F'(3) = 31

Answer 2

It seems like you've provided a function $F(x) = \frac{1}{3}x^3 - \frac{1}{2}x^2 - 2x + 1$ and an initial value $x_0 = 1$. It looks like you might want to perform some calculations or analysis related to this function and initial value. Could you please specify what you would like to do with this information? Are you looking for the value of the function at $x_0$, or do you have a different question in mind?