Question

1. (х-3,7) • (х+3) =0 2. х•(х+4) • (3,2-х)=0

Answer 1

Ответ:

Пошаговое объяснение:

1.(х-3,7) • (х+3) =0

1. х²+х3-х3.7+11.1=0
2. х²-х0.7+11.1=0
3. Д=в²-4ас=0.49-44.4=−43,91
4. Корней нет.

2.х•(х+4) • (3,2-х)=0

1. 3.2х-х²+12.8-4х=0
2. -х²-0.8х+12.8=0
3. Д=в²-4ас=0.64+51,2=51.84

Answer 2

It looks like you've provided two equations involving variables. Let's solve each equation separately:

1. $(x - 3) \cdot (x + 3) = 0$

To solve this equation, we set each factor equal to zero and solve for $x$:

$x - 3 = 0 \Rightarrow x = 3$

$x + 3 = 0 \Rightarrow x = -3$

So, the solutions for the equation are $x = 3$ and $x = -3$.

2. $x \cdot (x + 4) \cdot (3.2 - x) = 0$

Similarly, we'll set each factor equal to zero and solve for $x$:

$x = 0$

$x + 4 = 0 \Rightarrow x = -4$

$3.2 - x = 0 \Rightarrow x = 3.2$

So, the solutions for the equation are $x = 0$, $x = -4$, and $x = 3.2$.

These are the solutions for the given equations.