Question

(x+3)(x+1)-3(x+3)+20

Answer 1

To simplify the expression $(x+3)(x+1)-3(x+3)+20$, follow these steps:

1. Distribute the terms in the first parentheses: $(x+3)(x+1) = x(x+1) + 3(x+1) = x^2 + x + 3x + 3 = x^2 + 4x + 3$.

2. Distribute the -3 into the second parentheses: $-3(x+3) = -3x - 9$.

Now, the expression becomes: $x^2 + 4x + 3 - 3x - 9 + 20$.

3. Combine like terms: $x^2 + (4x - 3x) + (3 - 9) + 20 = x^2 + x - 6 + 20$.

4. Combine the constants: $x^2 + x + 14$.

So, the simplified expression is $x^2 + x + 14$.