Question

1) 7y - (5 - y) = 11 2) 3x + 6 = 3 * (x + 1) + 3

Answer 1

Ответ:

1) 7y - (5 - y) = 11

7у-5+у=11

8у=11+5

8у=16|:8

у=2

2) 3x + 6 = 3 * (x + 1) + 3

3х+6=3х+3+3

3х-3х=6-6

0=0

Значение х может быть любым

Answer 2

Sure, I can help you solve these equations step by step:

1. $7y - (5 - y) = 11$

First, let's simplify the equation by distributing the negative sign through the parentheses:

$7y - 5 + y = 11$

Combine the y terms:

$8y - 5 = 11$

Now, add 5 to both sides of the equation:

$8y = 16$

Finally, divide both sides by 8 to solve for y:

$y = 2$

So, the solution for the first equation is $y = 2$.

2. $3x + 6 = 3 \cdot (x + 1) + 3$

Start by distributing the 3 on the right side of the equation:

$3x + 6 = 3x + 3 + 3$

Combine the constants on the right side:

$3x + 6 = 3x + 6$

Subtract $3x$ from both sides:

$6 = 6$

The equation $6 = 6$ is always true, which means the original equation is an identity. This means that the equation is true for all values of $x$, and there is no unique solution for $x$.

So, the second equation doesn't have a unique solution for $x$.