Question

40-42÷x=33 7×(x÷3)=28 (a×80)÷4=120​

Answer 1

Ответ:

х=6,х=12,а=6

Пошаговое объяснение:

1.

40-42÷x=33

перенесем 33 с противоположным знаком налево, а -(42÷x) с + направо:

40-33=42÷x

42÷x=7

x=42÷7

x=6

2.

7×(x÷3)=28

x÷3=28÷7

x÷3=4

x=4*3

x=12

3.

(a×80)÷4=120​

a×80=120*4

a×80=480

a=480÷80

a=6

Answer 2

Let's solve each equation step by step:

1. 40 - 42 ÷ x = 33:

To solve this equation, we'll start by isolating the variable x.

Subtract 40 from both sides: 40 - 42 ÷ x - 40 = 33 - 40 -42 ÷ x = -7

Next, we can multiply both sides by x to eliminate the fraction: (-42 ÷ x) * x = -7 * x -42 = -7x

Now, divide both sides by -7 to solve for x: -42 / -7 = x 6 = x

Therefore, x = 6.

2. 7 × (x ÷ 3) = 28:

To solve this equation, we'll follow the order of operations (PEMDAS/BODMAS).

First, we'll simplify the expression inside the parentheses: x ÷ 3 = 28 ÷ 7 x ÷ 3 = 4

Next, multiply both sides by 3 to isolate x: (x ÷ 3) * 3 = 4 * 3 x = 12

So, x = 12.

3. (a × 80) ÷ 4 = 120:

To solve this equation, we'll isolate the variable a.

Multiply both sides by 4 to eliminate the fraction: ((a × 80) ÷ 4) * 4 = 120 * 4 a × 80 = 480

Now, divide both sides by 80 to solve for a: (a × 80) / 80 = 480 / 80 a = 6

Hence, a = 6.