Question

M÷5/11=-1 7/15; x÷1 1/7=-7/9; 1/3x-1=15-x​

Answer 1

Ответ:

$m \div \frac{5}{11} = - 1 \frac{7}{15} \\ m = - 1 \frac{7}{15} \times \frac{5}{11} = - \frac{22}{15} \times \frac{5}{11}$

$m = - \frac{2}{3}$

$x \div 1 \frac{1}{7} = - \frac{7}{9} \\ x = - \frac{7}{9} \times 1 \frac{1}{7} = - \frac{7}{9} \times \frac{8}{7}$

$x = - \frac{8}{9}$

$\frac{1}{3} x - 1 - 15 + x = 0 \\ 1 \frac{1}{3} x - 16 = 0 \\ 1 \frac{1}{3} x = 0 + 16$

$1 \frac{1}{3} x = 16 \\ x = 16 \div 1 \frac{1}{3} = 16 \times \frac{3}{4}$

$x = 12$

Answer 2

It seems like you've provided a system of equations. Let's solve each equation step by step:

1. M ÷ 5/11 = -1 7/15: To solve this equation, we can multiply both sides by the reciprocal of 5/11, which is 11/5.

   M * (11/5) = -1 7/15 * (11/5) M = -1 7/15 * 11/5 M = -11/3 + 77/75 M = (-55 + 77) / 75 M = 22/75

2. x ÷ 1 1/7 = -7/9: To solve this equation, we'll first convert 1 1/7 to an improper fraction (8/7). Then, we can multiply both sides by the reciprocal of -7/9, which is -9/7.

   x * (-9/7) = -7/9 * (8/7) x = 56/63

3. 1/3x - 1 = 15 - x: Let's solve for x in this equation.

   Add x to both sides: 1/3x + x - 1 = 15

   Combine the x terms: 4/3x - 1 = 15

   Add 1 to both sides: 4/3x = 16

   Multiply both sides by 3/4 to solve for x: x = (16 * 3) / 4 x = 12

So, the solutions to the equations are:

1. M = 22/75
2. x = 56/63
3. x = 12