Question

(b-1) (b +1)-(a+1)(a-1)

Answer 1

Ответ:

$(b-1)(b+1)-(a+1)(a-1)=(b^2-1)-(a^2-1)=b^2-a^2$

или

$(b-a)(b+a)$

Answer 2

Відповідь:

b²-a²

Покрокове пояснення:

(b-1) (b +1)-(a+1)(a-1)=b*b+b*1-1*b-1*1-(a*a+a*(-1)+1*a+1*(-1))=b²+b-b-1-(a²-a+a-1)=

b²-1-(a²-1)=b²-1-a²-(-1)=b²-1-a²+1=b²-a²=(b-a)(b+a)

Answer 3

To simplify the expression (b-1) (b +1)-(a+1)(a-1), we can expand it using the distributive property and then simplify further. Let's break it down step by step:

Step 1: Expand the expression (b-1) (b +1) - (a+1)(a-1) = (b^2 + b - b - 1) - (a^2 - a + a - 1)

Step 2: Simplify the terms within each set of parentheses (b^2 - 1) - (a^2 - 1)

Step 3: Apply the distributive property b^2 - 1 - a^2 + 1

Step 4: Combine like terms (b^2 - a^2) + (-1 + 1)

Step 5: Simplify further (b^2 - a^2) + 0

Step 6: Final simplified expression b^2 - a^2

So, the expression (b-1) (b +1)-(a+1)(a-1) simplifies to b^2 - a^2.