Question

(2a-3)^2+(3-2a)(3+2a)-3(a+2)(3a-1)

Answer 1

Ответ:

-9a^2 - 27a + 24

Пошаговое объяснение:

(2a-3)^2+(3-2a)(3+2a)-3(a+2)(3a-1) = 4a^2 - 12a + 9 + (9 - 4a^2) - 3(3a^2 - a + 6a - 2) = 4a^2 -12a + 18 - 4a^2 - 9a^2 + 3a - 18a + 6 = 4a^2 - 27a + 24 - 13a^2 = -9a^2 - 27a + 24

Answer 2

Let's simplify the given expression step by step:

Expression: (2a - 3)^2 + (3 - 2a)(3 + 2a) - 3(a + 2)(3a - 1)

Step 1: Expand the squared term (2a - 3)^2 (2a - 3)^2 = (2a - 3)(2a - 3) = 4a^2 - 6a - 6a + 9 = 4a^2 - 12a + 9

Step 2: Expand the product of the two binomials (3 - 2a)(3 + 2a) (3 - 2a)(3 + 2a) = 9 + 6a - 6a - 4a^2 = 9 - 4a^2

Step 3: Expand the product 3(a + 2)(3a - 1) 3(a + 2)(3a - 1) = 3(a * (3a - 1) + 2 * (3a - 1)) = 3(3a^2 - a + 6a - 2) = 9a^2 + 15a - 6

Now, let's put all these results back into the original expression and simplify:

Expression = (4a^2 - 12a + 9) + (9 - 4a^2) - (9a^2 + 15a - 6)

Combine like terms: Expression = 4a^2 - 12a + 9 + 9 - 4a^2 - 9a^2 - 15a + 6

Simplify further: Expression = -9a^2 - 22a + 24

So, the simplified form of the expression is -9a^2 - 22a + 24.