Question

X^2-5x+10=0 ______________________________

Answer 1

дискриминант=25-4*1*10=-15, дискриминант получился отрицательный, значит корней у уравнения нет

Answer 2

Ответ:

x^2-5x+10=0

D=25-4*10=25-40<0

корней нет

Answer 3

The equation you've provided is a quadratic equation in terms of the variable x:

x^2 - 5x + 10 = 0

This equation cannot be factored easily into linear terms. To solve for the values of x, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In this equation, the coefficients are: a = 1 (coefficient of x^2) b = -5 (coefficient of x) c = 10 (constant term)

Plugging these values into the quadratic formula:

x = (-(-5) ± √((-5)² - 4 * 1 * 10)) / (2 * 1) x = (5 ± √(25 - 40)) / 2 x = (5 ± √(-15)) / 2

Since the term inside the square root is negative, the solutions will be complex numbers. The square root of -15 can be written as √15 * √(-1), which is denoted as "i" (the imaginary unit). So the solutions are:

x = (5 ± √15 * i) / 2

These are the complex solutions for the given quadratic equation.