Question

1. (9-2b)-(b+5)=16 2. -6x+2(5-3x)=8 3. 4(-2z+5)=14-2(4z-3) 4. 12a-1=-a+25 5. 4n=-2+6n+7 6. -3d-10=3d-6 7. -2n=5,6n 8. 3(-5+c)-2(c-4)=2-7(c-1)

Answer 1

Ответ:

1. b= -4

2. x=2/12

3. Бесконечное множество корней

4. a=2

5. n= -2,5

6. d=⅔

7. n=0

8. c=2

Пошаговое объяснение:

1. (9-2b)-(b+5)=16

9-2b-b-5=16

-3b=16+5-9

-3b=12

b= -4

2. -6x+2(5-3x)=8

-6x+10-6x=8

-12x=-2

x=2/12

3. 4(-2z+5)=14-2(4z-3)

-8z+20=14-8z+6

-8z+8z=20-20

0z=0 => бесконечное множество корней

4. 12a-1=-a+25

12a+a=25+1

13a=26

a=2

5. 4n=-2+6n+7

4n-6n=7-2

-2n=5

n=-2,5

6. -3d-10=3d-6

-3d-3d=10-6

-6d=4

d=4/6=⅔

7.-2n=5,6n

-2n-5,6n=0

-7,6n=0

n=0

8. 3(-5+c)-2(c-4)=2-7(c-1)

-15+3c-2c+8=2-7c+7

3c-2c+7c=2+7-8+15

8c=16

c=2

Answer 2

Ответ:

Пошаговое объяснение:

1.

(9-2b)-(b+5)=16

9 - 2b - b - 5 = 16

-3b + 4 = 16

3b = 4 - 16

3b = -12

b = -12 : 3

b = -4

2.

-6x+2(5-3x)=8

-6x + 10 - 6x = 8

-12x + 10 = 8

12x = 10 - 8

12x = 2

x = 2 : 12

x = 1/6

3.

4(-2z+5)=14-2(4z-3)

-8z + 20 = 14 - 8z + 6

-8z + 20 = 20 - 8z

8z - 8z = 20 - 20

0 = 0

z є (-∞ ; ∞)

уравнение имен множество корней

4.

12a-1=-a+25

12a + a = 25 + 1

13a = 26

a = 26 : 13

a = 2

5.

4n=-2+6n+7

4n = 5 + 6n

6n - 4n = -5

2n = -5

n = -5 : 2

n = -2,5

6.

-3d-10=3d-6

-3d - 3d = 10 - 6

-6d = 4

d = 4 : 6

d = 2/3

7.

-2n=5,6n

-2n - 5,6n = 0

-7,6n = 0

n = 0

8.

3(-5+c)-2(c-4)=2-7(c-1)

-15 + 3c - 2c + 8 = 2 - 7c + 7

-7 + c = 9 - 7c

c + 7c = 9 + 7

8c = 16

c = 16 : 8

c = 2

Answer 3

It looks like you've provided a list of equations. It seems that you would like help solving these equations for the respective variables. I'll go through each equation and solve for the indicated variable:

1. $(9 - 2b) - (b + 5) = 16$ Simplify: $9 - 2b - b - 5 = 16$ Combine like terms: $4 - 3b = 16$ Subtract 4 from both sides: $-3b = 12$ Divide by -3: $b = -4$

2. $-6x + 2(5 - 3x) = 8$ Distribute 2: $-6x + 10 - 6x = 8$ Combine like terms: $-12x + 10 = 8$ Subtract 10 from both sides: $-12x = -2$ Divide by -12: $x = \frac{1}{6}$

3. $4(-2z + 5) = 14 - 2(4z - 3)$ Distribute on both sides: $-8z + 20 = 14 - 8z + 6$ Combine like terms: $-8z + 20 = -8z + 20$ This equation is an identity, meaning it's true for all values of $z$.

4. $12a - 1 = -a + 25$ Add $a$ to both sides: $13a - 1 = 25$ Add 1 to both sides: $13a = 26$ Divide by 13: $a = 2$

5. $4n = -2 + 6n + 7$ Combine like terms: $4n = 6n + 5$ Subtract $6n$ from both sides: $-2n = 5$ Divide by -2: $n = -\frac{5}{2}$

6. $-3d - 10 = 3d - 6$ Add $3d$ to both sides: $-6d - 10 = -6$ Add 10 to both sides: $-6d = 4$ Divide by -6: $d = -\frac{2}{3}$

7. $-2n = 5,6n$ It seems like there might be a typo in the equation. It's unclear what the equation is supposed to be. Could you please clarify?

8. $3(-5 + c) - 2(c - 4) = 2 - 7(c - 1)$ Distribute on both sides: $-15 + 3c - 2c + 8 = 2 - 7c + 7$ Combine like terms: $c - 7 = -5c + 9$ Add $5c$ to both sides: $6c - 7 = 9$ Add 7 to both sides: $6c = 16$ Divide by 6: $c = \frac{8}{3}$

If you need further clarification or assistance, please feel free to ask!