Question

(7+2i)(8-3i)+(7-2i)(8+3i)

Answer 1

Ответ:

124

Пошаговое объяснение:

Приступлю к решению:

(7+2i)(8-3i)+(7-2i)(8+3i)

i² = -1

(7+2i)(8-3i)=56-21i+16i+6=62-5i

(7-2i)(8+3i)=56+21i-16i+6=5i+62

62-5i+5i+62=62+62=124

Answer 2

Let's simplify the given expression step by step:

(7 + 2i)(8 - 3i) + (7 - 2i)(8 + 3i)

First, let's multiply the terms in each set of parentheses:

For the first term: (7 + 2i)(8 - 3i) = 7 * 8 + 7 * (-3i) + 2i * 8 + 2i * (-3i) = 56 - 21i + 16i - 6i^2

Now, remember that i^2 is equal to -1, so we can substitute that in:

= 56 - 5i - 6(-1) = 56 - 5i + 6 = 62 - 5i

For the second term: (7 - 2i)(8 + 3i) = 7 * 8 + 7 * 3i - 2i * 8 - 2i * 3i = 56 + 21i - 16i - 6i^2

Again, substitute i^2 with -1:

= 56 + 5i - 6(-1) = 56 + 5i + 6 = 62 + 5i

Now, let's add the two results:

(62 - 5i) + (62 + 5i) = 62 - 5i + 62 + 5i = 124

So, the simplified expression is 124.