Question

Log4(3x-7)=log4(2x+1)

Answer 1

Ответ:

Пошаговое объяснение:

log4(3x-7)=log4(2x+1)

итак, основание логарифма одинаковое, значит..

3х-7=2х+1

x=8

Но 3х-7>0 и 2x+1>0

x>7/3 и x>-0,5

х=8 удовлетворяет условиям..

ответ: 8

Answer 2

To solve the equation log₄(3x - 7) = log₄(2x + 1), we can use the properties of logarithms. The key property we'll use here is that if the logarithms have the same base and are equal, then their arguments must be equal as well. In this case, the base is 4.

So, we have:

log₄(3x - 7) = log₄(2x + 1)

Since the bases are the same, we can set the arguments equal to each other:

3x - 7 = 2x + 1

Now, we can solve for x:

3x - 2x = 1 + 7

x = 8

So, the solution to the equation is x = 8.