Question

√-x=4 плізззззззззззз

Answer 1

Ответ:

Пошаговое объяснение

√-х=4

-х=4²

-х=16

х=-16

Answer 2

Ответ:

x=-16

Пошаговое объяснение:

-x=16

↓

x=-16

Answer 3

The equation √(-x) = 4 involves taking the square root of a negative number, which is not defined in the real number system. However, we can work with complex numbers, where the square root of a negative number is defined.

To solve the equation, we'll consider x as a complex number. Let's assume x = a + bi, where a and b are real numbers and i is the imaginary unit (√(-1)).

√(-x) = √(-(a + bi)) = √(-a - bi) = √((-a) * (1 + i))

To simplify further, we'll convert 1 + i into polar form: 1 + i = √2 * (∠45°) or √2 * (∠π/4)

Now, let's rewrite the equation:

√(-x) = √((-a) * (1 + i)) = √(-a) * √(1 + i) = √(-a) * √2 * (∠π/8)

Setting this equal to 4:

√(-a) * √2 * (∠π/8) = 4

To isolate √(-a), we divide both sides by √2 * (∠π/8):

√(-a) = 4 / (√2 * (∠π/8))

Now, to find the value of √(-a), we need to calculate the right side of the equation:

4 / (√2 * (∠π/8)) = 4 / (√2 * (cos(π/8) + isin(π/8))) = 4 / (√2 * (√2/2 + i√2/2)) = 4 / (1 + i)

To rationalize the denominator, we multiply the numerator and denominator by the conjugate of 1 + i:

(4 / (1 + i)) * ((1 - i) / (1 - i)) = (4 * (1 - i)) / (1^2 - i^2) = (4 - 4i) / (1 - (-1)) = (4 - 4i) / 2 = 2 - 2i

So, √(-a) = 2 - 2i.

Now, to find the value of a, we square both sides of √(-a) = 2 - 2i:

(-a) = (2 - 2i)^2 = (2 - 2i)(2 - 2i) = 4 - 4i - 4i + 4i^2 = 4 - 8i - 1 = 3 - 8i

To isolate a, we multiply both sides by -1:

a = -3 + 8i

So, the solution to the equation √(-x) = 4 is x = -3 + 8i.