Question

6!(4!+5!) /( 8!+10!) факториал

Answer 1

$\frac{6!(4!+5!)}{( 8!+10!) } = \frac{6!(4!+5*4!)}{( 8!+10 *9*8!) } = \frac{6!*6*4!}{8!+90*8! } = \frac{6!*6*4*3!}{91 *8! } = \frac{6!*6*4*3!}{91 *8*7*6! } = \frac{3*4*3!}{91*4*7} = \frac{3*3!}{91 *7 } = \frac{3*6}{637 } = \frac{18}{637}$

Answer 2

To simplify the expression, let's start by calculating the factorials involved:

6! = 6 × 5 × 4 × 3 × 2 × 1 = 720

4! = 4 × 3 × 2 × 1 = 24

5! = 5 × 4 × 3 × 2 × 1 = 120

8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320

10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800

Now we can substitute these values into the expression:

6!(4! + 5!) / (8! + 10!) = 720(24 + 120) / (40,320 + 3,628,800) = 720(144) / 3,669,120 = 103,680 / 3,669,120 ≈ 0.028252

Therefore, 6!(4! + 5!) / (8! + 10!) is approximately equal to 0.028252.