Question

(2y-3)(3y+1)+2(y+5)=2(1-2y)+6y²

Answer 1

Ответ:

Пошаговое объяснение:

6y²+2y-9y-3+2y+10=2-4y+6y²

-y=-5

y=5

Answer 2

Ответ в фото. Надеюсь поможет

Answer 3

To solve the given equation $(2y-3)(3y+1)+2(y+5)=2(1-2y)+6y^2$, we will first simplify and then solve for the value of $y$.

Let's start by expanding and simplifying both sides of the equation step by step:

Left-hand side: $(2y-3)(3y+1) = 2y(3y+1) - 3(3y+1) = 6y^2 + 2y - 9y - 3$ $\quad\quad\quad\quad\, = 6y^2 - 7y - 3$

So, the left-hand side of the equation becomes: $6y^2 - 7y - 3 + 2(y+5) = 6y^2 - 7y - 3 + 2y + 10 = 6y^2 - 5y + 7$.

Right-hand side: $2(1-2y) = 2 - 4y$ $6y^2$ remains unchanged.

So, the right-hand side of the equation remains: $2 - 4y + 6y^2$.

Now, our equation becomes: $6y^2 - 5y + 7 = 2 - 4y + 6y^2$.

To solve for $y$, we'll subtract $6y^2$ from both sides and then simplify:

$6y^2 - 6y^2 - 5y + 7 = 2 - 6y^2 - 4y$ $-5y + 7 = 2 - 4y$

Next, let's isolate $y$ terms on one side by adding $4y$ to both sides:

$-5y + 4y + 7 = 2$ $-y + 7 = 2$

Subtract $7$ from both sides:

$-y = -5$

Finally, multiply both sides by $-1$ to solve for $y$:

$y = 5$

So, the solution to the equation is $y = 5$.