Question

F(x)=x'2-3x ,x=-1;2,5;3​

Answer 1

Ответ: f(-1)=1+3=4

F(2)=4-3*2=4-6=-2

F(3)=9-3*2=9-6=3

F(5)=25-2*5=15.

Пошаговое объяснение:

Answer 2

To evaluate the function $F(x) = x'^2 - 3x$ at the given values $x = -1, 2.5, 3$, we substitute each value of $x$ into the function and calculate the corresponding $F(x)$ value.

1. For $x = -1$: $F(-1) = (-1)^2 - 3(-1)$ $F(-1) = 1 + 3$ $F(-1) = 4$

2. For $x = 2.5$: $F(2.5) = (2.5)^2 - 3(2.5)$ $F(2.5) = 6.25 - 7.5$ $F(2.5) = -1.25$

3. For $x = 3$: $F(3) = (3)^2 - 3(3)$ $F(3) = 9 - 9$ $F(3) = 0$

Therefore, the values of the function $F(x) = x'^2 - 3x$ at $x = -1, 2.5, 3$ are: $F(-1) = 4$, $F(2.5) = -1.25$, $F(3) = 0$.