Question

(3х-1)(2х+7)-(х+1)(6-5)=7​

Answer 1

Ответ:

Пошаговое объяснение:

(3х - 1) . (2х + 7) - (х + 1) . (6 - 5) = 7​

6х² + 21х - 2х - 7 - (6х - 5х + 6 - 5) = 7

6х² + 21х - 2х - 7 - 6х+5х-6+5 = 7

6х² + 18х =7 + 7 + 6 - 5

6х² +18х=15

6х² + 18х - 15 = 0   :3

2х² + 6х - 5 = 0

Д = 6²- 4 . 2 . 5

Д = 36 - 40 = -4

Нет решения

Answer 2

To solve the given equation, let's expand the expressions on both sides and simplify the equation.

Expanding the left side of the equation: (3x - 1)(2x + 7) - (x + 1)(6 - 5) = 7

Using the distributive property, we can expand each term: (3x)(2x) + (3x)(7) - (1)(2x) - (1)(7) - (x)(6) + (x)(5) = 7

Simplifying the terms: 6x^2 + 21x - 2x - 7 - 6x + 5 = 7

Combining like terms: 6x^2 + 19x - 2 = 7

Moving all terms to one side to set the equation to zero: 6x^2 + 19x - 2 - 7 = 0

Simplifying further: 6x^2 + 19x - 9 = 0

Now we have a quadratic equation in standard form. To solve it, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 6, b = 19, and c = -9. Substituting these values into the quadratic formula:

x = (-19 ± √(19^2 - 4 * 6 * -9)) / (2 * 6)

Simplifying further:

x = (-19 ± √(361 + 216)) / 12 x = (-19 ± √577) / 12

Therefore, the solutions to the equation are: x = (-19 + √577) / 12 x = (-19 - √577) / 12