Question

2x + 4 < 01-4X > X – 2,5система​

Answer 1

2x + 4 < 0

1-4х > х – 2.5

___________

х<-4/2

-5x>-3.5

___________

x<-2

x<0.7

__________

x∈(-∞;-2)

Answer 2

It looks like you've provided two inequalities: $2x + 4 < 0$ and $-4x > x - 2.5$. To solve this system of inequalities, we need to find the range of values for $x$ that satisfy both inequalities simultaneously.

Let's solve each inequality separately:

1. $2x + 4 < 0$ Subtract 4 from both sides: $2x < -4$ Divide by 2 (remember that dividing by a negative number flips the inequality sign): $x < -2$

2. $-4x > x - 2.5$ Add $4x$ to both sides and subtract $x$ from both sides: $-5x > -2.5$ Divide by -5 (and reverse the inequality sign): $x < 0.5$

Now we have the individual solutions for each inequality: $x < -2$ and $x < 0.5$.

To satisfy both inequalities simultaneously, $x$ must be a value that is both less than -2 and less than 0.5. The only values that fulfill this condition are those that are less than -2, since any value less than -2 will automatically be less than 0.5.

So, the solution for the system of inequalities is $x < -2$.