Question

1)|-x|=3,1; 2)|-x|=82; 3)|-x|=5/32; 4)|-x|=17 20/23​

Answer 1

1)|-x|=3,1
|x|=3,1
x=3,1
x=-3,1
x1=-3,1;x2=3,1
2)|-x|=82
|x|=82
x=82
x=-82
x1=-82;x2=82
3)|-x|=5/32
|x|=5/32
x=5/32
x=-5/32
x1=-5/32;x2=5/32
4)|-x|=17
|x|=17
x=17
x=-17
x1=-17;x2=17

Answer 2

It seems like you've provided a list of equations involving the absolute value of an unknown variable, "-x". To solve these equations, you'll need to isolate the absolute value term and consider both the positive and negative cases for the unknown variable. Let's solve these equations one by one:

1. |-x| = 3 In this case, the absolute value of -x is equal to 3. This implies that -x can be either 3 or -3. So, you have two possible solutions: x = -3 and x = 3.

2. |-x| = 82 Here, the absolute value of -x is equal to 82. This means that -x can be either 82 or -82. So, you have two possible solutions: x = -82 and x = 82.

3. |-x| = 5/32 The absolute value of -x is equal to 5/32. This gives you two possible solutions: x = -5/32 and x = 5/32.

4. |-x| = 17 20/23 In this case, the absolute value of -x is equal to 17 20/23. This results in two possible solutions: x = -17 20/23 and x = 17 20/23.

Remember that when solving absolute value equations, you consider both the positive and negative values that satisfy the equation. Each equation provides two potential solutions due to the nature of absolute values.