Question

10x^2 - 30x + 50 = 0

Answer 1

$10x^{2} -30x+50=0$

a=10 , b = -30 , c = 50

$D=b^{2} -4ac = (-30)^{2} -4*10*50=900-2000 = -1100$

Так как дискриминант меньше нуля, то уравнение не имеет действительных решений

Answer 2

The equation you've provided is a quadratic equation in terms of the variable "x." It's in the standard form:

10x^2 - 30x + 50 = 0

To solve this quadratic equation, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In your equation, the coefficients are: a = 10 b = -30 c = 50

Plug these values into the quadratic formula:

x = (-(-30) ± √((-30)² - 4 * 10 * 50)) / (2 * 10) x = (30 ± √(900 - 2000)) / 20 x = (30 ± √(-1100)) / 20

Since the term inside the square root is negative, the solutions will involve imaginary numbers. You can represent the square root of -1100 as √(1100)i, where "i" is the imaginary unit (√-1):

x = (30 ± √(1100)i) / 20

So, the solutions for "x" are:

x = (30 + √(1100)i) / 20 x = (30 - √(1100)i) / 20

These are the complex solutions to the quadratic equation.