Question

199-195+194-190+189-185+184-180+...+14-10+9-5+4

Answer 1

Ответ:

179

Пошаговое объяснение:

Answer 2

199-195+194-190+189-185+184-180+179+14-10+9-5+4

Answer 3

It looks like you're trying to calculate the sum of a series of numbers where you're alternating between subtracting and adding consecutive numbers. If I understand correctly, you want to compute:

199 - 195 + 194 - 190 + 189 - 185 + 184 - 180 + ... + 14 - 10 + 9 - 5 + 4

To simplify this, let's group the numbers in pairs:

(199 - 195) + (194 - 190) + (189 - 185) + (184 - 180) + ... + (14 - 10) + (9 - 5) + 4

Now, let's calculate each of these pairs:

4 + 4 + 4 + 4 + ... + 4 + 4 + 4 = 4 * (number of pairs)

To find the number of pairs, let's count how many terms we have in the original sequence. We are counting from 199 down to 4 with a step of 5:

199, 194, 189, 184, ..., 9, 4

The common difference is 5, and the first term is 199, the last term is 4. We can use the formula for the nth term of an arithmetic sequence to find the number of terms:

nth term = first term + (n - 1) * common difference

4 = 199 + (n - 1) * 5 -195 = (n - 1) * 5 n - 1 = -39 n = -38

It seems like there's an issue here. The number of terms cannot be negative. It appears that there might be an error in the given sequence or the way it's presented. Could you please double-check the sequence or provide more context?