Question

1)3 3/5:X=9/35 2)8 4/15 - 5 2/5X= 4 2/3 3)(10-1 17/27:22\45) :4 4/9

Answer 1

Відповідь:

1)

$3\frac{3}{5} : x = \frac{9}{35}$

$\frac{18}{5} : x = \frac{9}{35}$

$x = \frac{18}{5} : \frac{9}{35}$

$x = \frac{18}{5} * \frac{35}{9}$

х=14

Покрокове пояснення:

Answer 2

It looks like you've provided three equations with variables. Let's solve them step by step:

Equation 1: $3 \frac{3}{5} : X = \frac{9}{35}$

First, let's convert the mixed number to an improper fraction for easier calculations:

$3 \frac{3}{5} = \frac{18}{5}$

Now the equation becomes:

$\frac{18}{5} : X = \frac{9}{35}$

To solve for $X$, we can multiply both sides by $X$:

$\frac{18}{5} = \frac{9}{35} \cdot X$

Now, solve for $X$:

$X = \frac{\frac{18}{5}}{\frac{9}{35}}$

Simplify:

$X = \frac{18}{5} \cdot \frac{35}{9} = \frac{1260}{45} = \frac{28}{1} = 28$

Equation 2: $8 \frac{4}{15} - 5 \frac{2}{5}X = 4 \frac{2}{3}$

First, convert the mixed numbers to improper fractions:

$8 \frac{4}{15} = \frac{124}{15}$ $5 \frac{2}{5} = \frac{27}{5}$ $4 \frac{2}{3} = \frac{14}{3}$

Now, the equation becomes:

$\frac{124}{15} - \frac{27}{5}X = \frac{14}{3}$

To solve for $X$, isolate $X$ on one side of the equation:

$-\frac{27}{5}X = \frac{14}{3} - \frac{124}{15}$

Find a common denominator for the fractions:

$-\frac{27}{5}X = \frac{70}{15} - \frac{124}{15}$

$-\frac{27}{5}X = -\frac{54}{15}$

Now solve for $X$:

$X = \frac{-\frac{54}{15}}{-\frac{27}{5}}$

Simplify:

$X = \frac{54}{27} = 2$

Equation 3: $\frac{10 - 1 \frac{17}{27}}{22 \frac{45}{4}} : 4 \frac{4}{9}$

Convert mixed numbers to improper fractions:

$1 \frac{17}{27} = \frac{44}{27}$ $22\frac{45}{4}=$ 0 0