Question

1 1/2 +x=3/4; 2 3/4-x=7/2; 3) x+1 1/8=2. 1/2​

Answer 1

Ответ:

._._._._._._._._._.

Answer 2

Ответ:

-0,75

-0,75

1,375

Пошаговое объяснение:

1 1/2 + х = 3/4

1 2/4 + х = 3/4

х = -3/4 = -0,75

2 3/4 - х = 7/2

2 3/4 - х = 3 2/4

х = -3/4 = -0,75

х + 1 1/8 = 2 1/2

х + 1 1/8 = 2 4/8

х = 1 3/8 = 1,375

Answer 3

Let's solve each of these equations step by step:

1. $1 \frac{1}{2} + x = \frac{3}{4}$

To solve for $x$, first, subtract $1 \frac{1}{2}$ from both sides of the equation:

$x = \frac{3}{4} - 1 \frac{1}{2}$

Now, find a common denominator for the fractions:

$x = \frac{3}{4} - \frac{3}{2}$

To subtract the fractions, they need a common denominator. The common denominator for 4 and 2 is 4, so we can rewrite $\frac{3}{2}$ as $\frac{3 \cdot 2}{2 \cdot 2}$:

$x = \frac{3}{4} - \frac{6}{4}$

Now, subtract the fractions:

$x = \frac{3 - 6}{4}$

$x = \frac{-3}{4}$

So, the solution to the first equation is $x = -\frac{3}{4}$.

2. $2 \frac{3}{4} - x = \frac{7}{2}$

To solve for $x$, first, subtract $2 \frac{3}{4}$ from both sides of the equation:

$-x = \frac{7}{2} - 2 \frac{3}{4}$

Find a common denominator for the fractions:

$-x = \frac{7}{2} - \frac{15}{4}$

To subtract the fractions, they need a common denominator. The common denominator for 2 and 4 is 4, so we can rewrite $\frac{7}{2}$ as $\frac{7 \cdot 2}{2 \cdot 2}$:

$-x = \frac{14}{4} - \frac{15}{4}$

Now, subtract the fractions:

$-x = \frac{14 - 15}{4}$

$-x = \frac{-1}{4}$

To solve for $x$, multiply both sides by -1:

$x = -\frac{-1}{4}$

$x = \frac{1}{4}$

So, the solution to the second equation is $x = \frac{1}{4}$.

3. $x + 1 \frac{1}{8} = 2 \frac{1}{2}$

To solve for $x$, first, subtract $1 \frac{1}{8}$ from both sides of the equation:

$x = 2 \frac{1}{2} - 1 \frac{1}{8}$

Find a common denominator for the fractions:

$x = 2 \frac{4}{8} - 1 \frac{1}{8}$

Now, subtract the fractions:

$x = 2 \frac{4 - 1}{8}$

$x = 2 \frac{3}{8}$

So, the solution to the third equation is $x = 2 \frac{3}{8}$.