Question

1)√-x=4 2)√x=-4 3)√x^2=16

Answer 1

1. -16

2. нет решения

3.16

Answer 2

Let's solve each of these equations:

1. √(-x) = 4

To solve this equation, we need to isolate x. First, square both sides to get rid of the square root:

(√(-x))^2 = 4^2

-x = 16

Now, multiply both sides by -1 to isolate x:

x = -16

So the solution to the first equation is x = -16.

2. √x = -4

This equation has no real solutions because the square root of a real number is always non-negative, and -4 is a negative number. Therefore, there are no real values of x that satisfy this equation.

3. √(x^2) = 16

Here, we have the square root of x^2, which is simply the absolute value of x:

|x| = 16

To find the solutions, we consider two cases:

Case 1: x is positive

If x is positive, then |x| is equal to x:

x = 16

Case 2: x is negative

If x is negative, then |x| is equal to -x:

-x = 16

Now, multiply both sides of the equation by -1 to isolate x:

x = -16

So, there are two solutions for this equation:

x = 16 and x = -16.