Question

1) 1,25 × х = 1 ; 2) 3 1/7 × х = 1 ; 3) 2 3/15 × х = 1.​

Answer 1

Ответ:

Пошаговое объяснение:

$1,25*x=1\\x=1:1,25\\x=0,8\\\\3\frac{1}{7}x=1\\x=1:\frac{22}{7}\\x=\frac{7}{22}\\\\2\frac{3}{15}x=1\\x=1:\frac{33}{15}\\x=\frac{15}{33}\\x=\frac{5}{11}$

Answer 2

To solve each of these equations for x, you can isolate x by dividing both sides of the equation by the coefficient of x. Here's how you can solve each equation:

1. $1.25x = 1$

To isolate x, divide both sides of the equation by 1.25:

$x = \frac{1}{1.25}$

Now, calculate the value of x:

$x = \frac{1}{1.25} = 0.8$

So, the solution to the first equation is $x = 0.8$.

2. $3\frac{1}{7}x = 1$

First, convert the mixed number to an improper fraction:

$3\frac{1}{7} = \frac{3 \cdot 7}{7} + \frac{1}{7} = \frac{21}{7} + \frac{1}{7} = \frac{22}{7}$

Now, the equation becomes:

$\frac{22}{7}x = 1$

To isolate x, divide both sides of the equation by $\frac{22}{7}$:

$x = \frac{1}{\frac{22}{7}}$

To divide by a fraction, multiply by its reciprocal:

$x = 1 \cdot \frac{7}{22} = \frac{7}{22}$

So, the solution to the second equation is $x = \frac{7}{22}$.

3. $2\frac{3}{15}x = 1$

First, simplify the mixed number:

$2\frac{3}{15} = \frac{2 \cdot 15}{15} + \frac{3}{15} = \frac{30}{15} + \frac{3}{15} = \frac{33}{15}$

Now, the equation becomes:

$\frac{33}{15}x = 1$

To isolate x, divide both sides of the equation by $\frac{33}{15}$:

$x = \frac{1}{\frac{33}{15}}$

To divide by a fraction, multiply by its reciprocal:

$x = 1 \cdot \frac{15}{33} = \frac{15}{33}$

You can simplify this fraction by finding the greatest common divisor (GCD) of 15 and 33, which is 3:

$\frac{15}{33} = \frac{15 \div 3}{33 \div 3} = \frac{5}{11}$

So, the solution to the third equation is $x = \frac{5}{11}$.