Question

(7-2/3):(1 3/4-1/6)×(1 1/5+2 2/3+1/6)=?​

Answer 1

Ответ:

(7-2/3):(1 3/4-1/6)*(1 1/5+2 2/3+1/6)

1)7-2/3=6 3/3-2/3=6 1/3

2)1 3/4-1/6=1 9/12-2/12=1 7/12

3)1 1/5+2 2/3=1 3/15+2 10/15=3 13/15

4)3 13/15+1/6=3 26/30+5/30=3 31/30=4 1/30

5)6 1/3:1 7/12=19/3:19/12=19/3*12/19=1/1*4/1=1*4=4

6)4*4 1/30=4*121/30=484/30=16 4/30=16 2/15

Ответ:16 2/15

Answer 2

To solve this expression, you should follow the order of operations (PEMDAS/BODMAS - Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction). Let's break it down step by step:

1. First, simplify the expressions inside the parentheses:

   • 7 - 2/3 = 21/3 - 2/3 = 19/3
   • 1 3/4 - 1/6 = 7/4 - 1/6 = 21/12 - 2/12 = 19/12
   • 1 1/5 + 2 2/3 + 1/6 = 6/5 + 8/3 + 1/6

2. Now, find a common denominator for the fractions in the last expression (step 1). The common denominator is 15:

   • 6/5 = 18/15
   • 8/3 = 40/15
   • 1/6 = 2/12 = 5/15

3. Add the fractions with the common denominator:

   • 18/15 + 40/15 + 5/15 = (18 + 40 + 5)/15 = 63/15

4. Now, divide the result from step 1 by the result from step 3:

   • (19/3) / (63/15)

To divide fractions, you can multiply by the reciprocal (flip the second fraction):

• (19/3) * (15/63)

5. Multiply the fractions:

   • (19/3) * (15/63) = (19 * 15) / (3 * 63) = 285 / 189

6. Simplify the fraction if possible. You can simplify by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 3:

   • (285 / 3) / (189 / 3) = 95 / 63

So, the final result is 95/63.