Question

(10-4b)(4b-10)=...(5+3a)(3a-4)=...​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

1)-16b2(в квадрате)+80b-100

Answer 3

To simplify the expressions (10-4b)(4b-10) and (5+3a)(3a-4), you can use the distributive property, also known as FOIL (First, Outer, Inner, Last) for multiplying binomials. Here's how you can do it for each expression:

1. (10-4b)(4b-10):

First, multiply the first terms in each binomial: (10 * 4b) = 40b

Then, multiply the outer terms: (10 * -10) = -100

Next, multiply the inner terms: (-4b * 4b) = -16b^2

Finally, multiply the last terms in each binomial: (-4b * -10) = 40b

Now, combine the like terms:

40b - 100 - 16b^2 + 40b

Combine the "b" terms: (40b + 40b) = 80b

So the simplified expression is:

-16b^2 + 80b - 100

2. (5+3a)(3a-4):

First, multiply the first terms in each binomial: (5 * 3a) = 15a

Then, multiply the outer terms: (5 * -4) = -20

Next, multiply the inner terms: (3a * 3a) = 9a^2

Finally, multiply the last terms in each binomial: (3a * -4) = -12a

Now, combine the like terms:

15a - 20 + 9a^2 - 12a

Combine the "a" terms: (15a - 12a) = 3a

So the simplified expression is:

9a^2 + 3a - 20

That's the simplified form of both expressions.