
23 2/5 + x = 4 5/6 + 21 1/6


Ответы на вопрос

Ответ:
x=83/5=16,6
!!!!!!!



х= 26-23 2/5
х= 2 3/5



To solve for the value of x in the equation:
23 2/5 + x = 4 5/6 + 21 1/6
You can start by simplifying both sides of the equation separately:
On the left side, 23 2/5 can be converted to an improper fraction: 23 2/5 = (5 * 23 + 2)/5 = (115 + 2)/5 = 117/5
So, the equation becomes:
117/5 + x = 4 5/6 + 21 1/6
Now, let's convert 4 5/6 and 21 1/6 to improper fractions as well:
4 5/6 = (6 * 4 + 5)/6 = (24 + 5)/6 = 29/6 21 1/6 = (6 * 21 + 1)/6 = (126 + 1)/6 = 127/6
Now, the equation looks like this:
117/5 + x = 29/6 + 127/6
To solve for x, first, find a common denominator for the fractions on the right side, which is 6. Then, add the fractions on the right side:
117/5 + x = (29/6 + 127/6)
Now, add the fractions on the right side:
117/5 + x = (29 + 127)/6 117/5 + x = 156/6
Now, simplify the fraction on the right side:
117/5 + x = 26
To isolate x, subtract 117/5 from both sides of the equation:
x = 26 - 117/5
To subtract these fractions, you need a common denominator, which is 5:
x = (5*26/5 - 117/5)
x = (130/5 - 117/5)
Now, subtract the numerators:
x = (130 - 117)/5
x = 13/5
So, the solution to the equation is:
x = 13/5


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