Question

Log0,3(2x+5)>log0,3(x+1)

Answer 1

Ответ:

2x+5<x+1

x<-4

Пошаговое объяснение:

Answer 2

To solve the inequality log₃(2x + 5) > log₃(x + 1), you can use the properties of logarithms.

First, recall the property that if logₐ(b) > logₐ(c), then b > c, assuming a > 1. In this case, a is 3, which is greater than 1, so the property applies.

So, you can rewrite the inequality as:

2x + 5 > x + 1

Now, you can solve for x:

2x - x > 1 - 5

x > -4

So, the solution to the inequality is x > -4.