Question

35-K>19 c-36<25 d+16>23 724:k>3​

Answer 1

$35 - k > 19 \\ - k > 19 - 35 \\ - k > 16 \\ k < 16$

k∈(-∞,16)

$c - 36 < 25 \\ c < 25 + 36 \\ c < 61$

c∈(-∞,61)

$d + 16 > 23 \\ d > 23 - 16 \\ d > 7$

d∈(7,+∞)

$724 \div k > 3 \\ \frac{724}{k} > 3 \\ \frac{724}{k} - 3 > 0 \\ \frac{724 - 3k}{k} > 0$

$k∈(0. \frac{724}{3} )$

Answer 2

It looks like you've provided a series of mathematical inequalities. Let me break them down for you:

1. $35 - K > 19$: This inequality suggests that when you subtract 19 from 35, the result should be greater than $K$. So, $K$ must be less than 16.

2. $C - 36 < 25$: This inequality indicates that when you add 36 to $C$, the result should be less than 25. So, $C$ must be less than 61.

3. $D + 16 > 23$: This inequality suggests that when you add 16 to $D$, the result should be greater than 23. So, $D$ must be greater than 7.

4. $724 : K > 3$: This inequality states that when you divide 724 by $K$, the result should be greater than 3. To satisfy this, $K$ must be less than 241.

So, summarizing:

• $K$ must be less than 16.
• $C$ must be less than 61.
• $D$ must be greater than 7.
• $K$ must be greater than 0. (Since dividing by 0 is undefined)
• $K$ must be less than 241 to satisfy the fourth inequality.