Question

1)4*a+36=6*10; 2)72-54:c=7×3+45; 3)42:7*4*8+y=6*8:1.

Answer 1

Ответ:

Пошаговое объяснение:

1) 4*a+36=6*10

4а=60-36

4а=24

а = 6

2) 72-54:c=7×3+45;

72-54/с=66

72-66-54/с=0

6-54/с=0

54/с = 6

с = 9

3)42:7*4*8+y=6*8:1

192+у = 48

у = -144

Answer 2

It looks like you've provided three equations, and it seems like you want to solve for the variable in each equation. Let's solve them one by one:

1. 4a + 36 = 6 * 10

First, simplify the right side:

4a + 36 = 60

Now, subtract 36 from both sides to isolate the term with 'a':

4a = 60 - 36 4a = 24

Finally, divide both sides by 4 to solve for 'a':

a = 24 / 4 a = 6

So, the solution for equation 1 is a = 6.

2. 72 - 54/c = 7 * 3 + 45

First, simplify the right side:

72 - 54/c = 21 + 45

Combine like terms on the right side:

72 - 54/c = 66

Now, subtract 72 from both sides to isolate the term with 'c' in the left:

-54/c = 66 - 72 -54/c = -6

Now, multiply both sides by -1 to make it positive:

54/c = 6

Finally, divide both sides by 6 to solve for 'c':

c = 54/6 c = 9

So, the solution for equation 2 is c = 9.

3. 42/7 * 4 * 8 + y = 6 * 8/1

First, perform the operations on both sides of the equation:

6 * 8/1 = 48

42/7 * 4 * 8 = 6 * 8

Now, the equation becomes:

48 + y = 48

To solve for 'y,' subtract 48 from both sides:

y = 48 - 48 y = 0

So, the solution for equation 3 is y = 0.