Question

2) 5|x| - 3 |x| = 33;4) 42 – 63|x|= 65|xl.​

Answer 1

Пошаговое объяснение:

2) 5 lxl-3 lxl=33

2* lxl=33

$|x1| = \frac{33}{2}$

$|x| = - \frac{33}{2}$

x1 = 33/2

x2= - 33/2

4)

-63*lxl - 65*lxl = - 42

-128*lxl = - 42

$|x1| = \frac{21}{64}$

$|x2| = - \frac{21}{64}$

Надеюсь правильно поняла ваше задание.

Answer 2

Let's solve the two equations:

1. $5|x| - 3 |x| = 33$

First, combine like terms on the left side of the equation:

$5|x| - 3 |x| = 2 |x|$

Now, isolate |x|:

$2 |x| = 33$

Divide both sides by 2:

$|x| = \frac{33}{2}$

Since the absolute value of a number is always positive, you have two cases to consider:

Case 1: $x = \frac{33}{2}$

Case 2: $x = -\frac{33}{2}$

So, the solutions are $x = \frac{33}{2}$ and $x = -\frac{33}{2}$.

Now, let's solve the second equation:

2. $42 - 63|x| = 65|x|$

First, combine like terms:

$42 = 128 |x|$

Now, isolate |x|:

$|x| = \frac{42}{128}$

Reduce the fraction:

$|x| = \frac{21}{64}$

Again, consider the two cases:

Case 1: $x = \frac{21}{64}$

Case 2: $x = -\frac{21}{64}$

So, the solutions are $x = \frac{21}{64}$ and $x = -\frac{21}{64}$.