Question

3) (x + 3)2 + (4 - x)2 = 2(x – 4)(x + 3).​

Answer 1

Ответ:

(x^3+2x^4-x)'=(x^3)'+2*(x^4)'-x'=3x^2+8x^3-1*x^0

Ответ: x^2*(8x+3)-1

Пошаговое объяснение:

Answer 2

Let's solve the given equation step by step:

(x + 3)² + (4 - x)² = 2(x - 4)(x + 3)

First, expand the squared terms:

(x² + 6x + 9) + (16 - 8x + x²) = 2(x² - 4x + 3x - 12)

Now, combine like terms on both sides of the equation:

x² + 6x + 9 + 16 - 8x + x² = 2(x² - x - 12)

Now, simplify further:

2x² + 25 - 8x = 2(x² - x - 12)

Next, distribute the 2 on the right side of the equation:

2x² + 25 - 8x = 2x² - 2x - 24

Now, subtract 2x² from both sides of the equation to eliminate the quadratic terms:

25 - 8x = -2x - 24

Next, add 8x to both sides to isolate the variable terms:

25 = 6x - 24

Now, add 24 to both sides:

49 = 6x

Finally, divide both sides by 6 to solve for x:

x = 49 / 6

So, the solution to the equation is:

x = 49 / 6

You can simplify this fraction if needed:

x = 8 1/6