Question

3) 1- x < 2x – 5;4) 2x + 1 > x + 6;​

Answer 1

Ответ:

3) 1-х<2x-5

-x-2x<-5-1

-3x<-6. |:-1

3x>6

x>2

4)2x+1>x+6

2x-x>6-1

x>5

Answer 2

To solve these inequalities, you can follow these steps:

3. $1 - x < 2x - 5$

First, add $x$ to both sides of the inequality:

$1 - x + x < 2x - 5 + x$

Simplify:

$1 < 3x - 5$

Now, add 5 to both sides:

$1 + 5 < 3x - 5 + 5$

Simplify:

$6 < 3x$

Finally, divide both sides by 3 to isolate $x$:

$\frac{6}{3} < \frac{3x}{3}$

Simplify:

$2 < x$

So, the solution to the first inequality is $x > 2$.

4. $2x + 1 > x + 6$

First, subtract $x$ from both sides of the inequality:

$2x + 1 - x > x + 6 - x$

Simplify:

$x + 1 > 6$

Now, subtract 1 from both sides:

$x + 1 - 1 > 6 - 1$

Simplify:

$x > 5$

So, the solution to the second inequality is $x > 5$.