Question

2) 25 - 5x > 0,3 x - 18 < 0;​

Answer 1

Ответ:

5 и 6

Пошаговое объяснение:

1) 25-5x>0

-5x>0-25

-5x>-25

5x>25

x>5

2) 3x-18<0

3x<0+18

3x<18

x<6

Answer 2

To solve the system of inequalities:

1. $25 - 5x > 0$
2. $3x - 18 < 0$

You can start by solving each inequality separately, and then find the intersection of the solutions:

1. Solve $25 - 5x > 0$:

First, subtract 25 from both sides:

$25 - 25 - 5x > 0 - 25$

$-5x > -25$

Now, divide both sides by -5, but remember that when you divide an inequality by a negative number, the direction of the inequality sign changes:

$-5x/-5 < -25/-5$

$x < 5$

So, the solution to the first inequality is $x < 5$.

2. Solve $3x - 18 < 0$:

Add 18 to both sides:

$3x - 18 + 18 < 0 + 18$

$3x < 18$

Now, divide both sides by 3:

$\frac{3x}{3} < \frac{18}{3}$

$x < 6$

So, the solution to the second inequality is $x < 6$.

Now, find the intersection of the two solutions, which means finding where both $x < 5$ and $x < 6$ are true. Since $x$ must satisfy both conditions:

$x < 5$ and $x < 6$

The solution is the smaller of the two values, which is $x < 5$.

So, the solution to the system of inequalities is:

$x < 5$