Question

3(2х+7)+x ⩾2(5+х)+1=

Answer 1

Ответ:

$3(2x + 7) + x \geqslant 2(5 + x) + 1 \\ 6x + 21 + x \geqslant 10 + 2x + 1 \\ 7x + 21 \geqslant 11 + 2x \\ 7x - 2x \geqslant 11 - 21 \\ 5x \geqslant - 10 \\ x \geqslant - 10 \div 5 \\ x \geqslant - 2$

[-2;+∞)

Answer 2

Ответ:

x = -2

Пошаговое объяснение:

3(2x + 7) + x = 2(5+x) + 1

6x + 21 + x = 10 + 2x + 1

7x - 2x = 11 - 21

5x = - 10

x = - 2

3(2x + 7) + x >= 2(5 + x) + 1

3 ( -4 + 7) - 2 >= 2 * 3 + 1

3 * 3 - 2 >= 7

7 >= 7

Answer 3

Let's solve the given inequality step by step:

3(2x + 7) + x ≥ 2(5 + x) + 1

First, distribute the numbers outside the parentheses:

6x + 21 + x ≥ 10 + 2x + 1

Now, combine like terms on both sides of the inequality:

7x + 21 ≥ 10 + 2x + 1

Combine constants:

7x + 21 ≥ 11 + 2x

Now, let's isolate the variable x by moving 2x from the right side to the left side by subtracting 2x from both sides of the inequality:

7x - 2x + 21 ≥ 11

This simplifies to:

5x + 21 ≥ 11

Now, subtract 21 from both sides:

5x + 21 - 21 ≥ 11 - 21

This simplifies to:

5x ≥ -10

Finally, divide both sides by 5 to solve for x:

(5x)/5 ≥ (-10)/5

This simplifies to:

x ≥ -2

So, the solution to the inequality is x ≥ -2.