Question

Sin(a+b)+Sin(a-b) / Sin(a+b)-Sin(a-b)

Answer 1

Ответ:зайди на сайт примеры плюс или формулой плюс и там просто всé правельное я всегда там набераю

Пошаговое объяснение:

Answer 2

The expression you've provided is:

$\frac{\sin(a+b) + \sin(a-b)}{\sin(a+b) - \sin(a-b)}$

To simplify this expression, we'll use trigonometric identities. Let's start by expanding the numerator and denominator using the sum and difference identities for sine:

Numerator: $\sin(a+b) + \sin(a-b) = \sin a \cos b + \cos a \sin b + (\sin a \cos b - \cos a \sin b)$ $= 2 \sin a \cos b$

Denominator: $\sin(a+b) - \sin(a-b) = \sin a \cos b + \cos a \sin b - (\sin a \cos b - \cos a \sin b)$ $= 2 \cos a \sin b$

Now, let's rewrite the original expression using these results:

$\frac{\sin(a+b) + \sin(a-b)}{\sin(a+b) - \sin(a-b)} = \frac{2 \sin a \cos b}{2 \cos a \sin b}$

The 2's cancel out, and we're left with:

$\frac{\sin a \cos b}{\cos a \sin b}$

Now, we can simplify further by canceling out common terms:

$\frac{\sin a}{\cos a} = \tan a$