Question

A1=--5 d=4 S10-? арифметичну прогресія​

Answer 1

Ответ:

Пошаговое объяснение:

а) а1 = 5, d = 3;

б) а1 = -8, d = 4;

в) а1 = 18,5, d = -2,5;

Sn = (a1 + an) * n / 2

an = a1 + d(n - 1)

а) an = 5 + 3(10 - 1)=5+27=32

Sn = (5 + 32) * 10 / 2 =37*5=185

Ответ: 185

б) an = (-8) + 4(10 - 1)=(-8)+36=28

Sn = ((-8) + 28) * 10 / 2 =20*5=100

Ответ: 100

an = 18 + (-2,5)(10 - 1)=18-22,5=-4,5

Sn = (18,5 - 4,5) * 10 / 2 =14*5=70

Ответ: 70

Answer 2

To find the 10th term (S10) of an arithmetic progression with the first term (A1) equal to -5 and a common difference (d) equal to 4, you can use the formula for the nth term of an arithmetic progression:

$A_n = A_1 + (n - 1) \cdot d$

In this case:

A1 = -5 d = 4 n = 10

Substitute these values into the formula:

$A_{10} = -5 + (10 - 1) \cdot 4$

Now, calculate the value:

$A_{10} = -5 + 9 \cdot 4$ $A_{10} = -5 + 36$ $A_{10} = 31$

So, the 10th term (A10) of the arithmetic progression is 31.