Question

X(x-3)(x+2,8)(9,1-x)=0​

Answer 1

Ответ:

равно нулю потому что я не знаю

Answer 2

To solve the given equation $X(x-3)(x+2.8)(9.1-x) = 0$, we can use the zero product property, which states that if $a \times b = 0$, then at least one of $a$ or $b$ must be equal to 0. In this case, we have four factors, so we can set each factor equal to 0 and solve for $x$:

1. $X = 0$
2. $x - 3 = 0 \Rightarrow x = 3$
3. $x + 2.8 = 0 \Rightarrow x = -2.8$
4. $9.1 - x = 0 \Rightarrow x = 9.1$

So, the solutions for $x$ are $X = 0$, $x = 3$, $x = -2.8$, and $x = 9.1$.