Question

815. 1) 2x + 3 = x - 6;3) 5 - 3y = 4 - 2y;5) 6a - 1 = 3a + 7;​

Answer 1

Ответ:

Пошаговое объяснение:

1) 2x + 3 = x - 6;

2x - x = -6 - 3

x = -9

3) 5 - 3y = 4 - 2y;

3y - 2y = 5 - 4

y = 1

5) 6a - 1 = 3a + 7;​

6a - 3a = 7+1

3a = 8

a = 8:3

a = 2 2/3

Answer 2

Пошаговое объяснение:

1)2х-х = -6-3

х=-9

3)-3у + 2у=4-5

-у=-1

у=1

5)6а-3а = 7+1

3а=8

а = 8 :3

а=8/3

Answer 3

To solve these equations, you'll need to isolate the variables. Here's how you can solve each of them step by step:

1. 2x + 3 = x - 6

First, you want to get all the x terms on one side of the equation and constants on the other side.

2x - x = -6 - 3 x = -9

So the solution for this equation is x = -9.

3. 5 - 3y = 4 - 2y

Again, you want to get all the y terms on one side and constants on the other side.

5 - 4 = 2y - 3y 1 = -y

Now, to isolate y, you can multiply both sides by -1:

1 * (-1) = (-y) * (-1) -1 = y

So the solution for this equation is y = -1.

5. 6a - 1 = 3a + 7

Like the previous equations, you'll want to group the "a" terms on one side and the constants on the other side.

6a - 3a = 7 + 1 3a = 8

Now, to isolate "a," divide both sides by 3:

(3a) / 3 = 8 / 3 a = 8/3

So the solution for this equation is a = 8/3.