Question

A) 2x - 3 = 15;6) (x+3)(3x – 7) = 0;B) 3,12x + = -0,412--0,9x​

Answer 1

Ответ:

1)X=15+3

X= 18

X=18:2

X=9

Answer 2

Покрокове пояснення:

2x - 3 = 15

2x = 15 + 3

2x =18

x =18:2

x =9

(x + 3)(3x - 7) = 0

x + 3 = 0            3x - 7 = 0

x = -3                3x  = 7

                          x = 2 1/3

А что за условие в третьем уравнении ?

Answer 3

It seems like you've provided two sets of equations labeled A and B. Let's solve them one by one:

A)

1. $2x - 3 = 15$

   Adding 3 to both sides:

   $2x = 18$

   Dividing both sides by 2:

   $x = 9$

2. $(x+3)(3x - 7) = 0$

   Using the zero-product property, either $x+3 = 0$ or $3x - 7 = 0$.

   For $x+3 = 0$, we have:

   $x = -3$

   For $3x - 7 = 0$, we have:

   $3x = 7$

   Dividing both sides by 3:

   $x = \frac{7}{3}$

So, the solutions for $x$ are $x = 9$, $x = -3$, and $x = \frac{7}{3}$.

B) I'm not sure if I understand the second equation correctly. It seems to be a bit unclear due to the notation. Could you please double-check the equation or provide more context?