Question

11 + 2х = 55 + 3х2. –15 – 3х = –7х + 453. –3х – 17 = 8х – 1054. 2(2 + y) = 19 – 3y5. (4 – c) + 2(c – 3) = –136. –3(3b + 1) – 12 = 12

Answer 1

Ответ:

Пошаговое объяснение:

11 + 2x = 55 + 3x

x = -44.

-15 - 3x = -7x + 45

4x = 60

x = 15

-3x - 17 = 8x - 105

11x = 88

x = 8

2(2 + y) = 19 - 3y

5y = 15

y = 3

4 - c + 2c - 6 = - 13

c = -3

-9b - 3 - 12 = 12

-9b = 3

b = - 1/3

Answer 2

Let's solve each equation step by step:

1. $11 + 2x = 55 + 3x^2$

   Rearrange the equation to form a quadratic equation:

   $3x^2 - 2x - 44 = 0$

   Now, you can solve this quadratic equation using the quadratic formula:

   $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

   For this equation, $a = 3$, $b = -2$, and $c = -44$.

   $x = \frac{2 \pm \sqrt{(-2)^2 - 4(3)(-44)}}{2(3)}$

   Simplify the expression inside the square root and solve for $x$.

2. $-15 - 3x = -7x + 453$

   Combine like terms and solve for $x$:

   $-15 + 453 = -7x + 3x$

   $438 = -4x$

   $x = -\frac{438}{4}$

3. $-3x - 17 = 8x - 1054$

   Combine like terms and solve for $x$:

   $-3x - 8x = -1054 + 17$

   $-11x = -1037$

   $x = \frac{-1037}{-11}$

4. $2(2 + y) = 19 - 3y$

   Distribute and solve for $y$:

   $4 + 2y = 19 - 3y$

   Combine like terms and solve for $y$.

5. $(4 - c) + 2(c - 3) = -136$

   Distribute and solve for $c$:

   $4 - c + 2c - 6 = -136$

   Combine like terms and solve for $c$.

6. $-3(3b + 1) - 12 = 12$

   Distribute and solve for $b$:

   $-9b - 3 - 12 = 12$

   Combine like terms and solve for $b$.

Please provide the solutions you obtain for each equation, and if you have any questions about specific steps, feel free to ask!