Question

1)6 6/7+5 1/3+6 1/7+7 2/32)5 7/10+7 12/19+8 3/10+ 100 7/19​

Answer 1

Ответ:

1) 26

2) 108

Пошаговое объяснение:

Используем сочитательный закон:

1) 6 6/7 + 6 1/7= 13;

5 1/3 + 7 2/3= 13;

13+13 = 26

2). 5 7/10 + 8 3/10 = 14

7 12/19 + 100 7/19 = 108

Answer 2

Sure, let's solve these addition problems step by step:

Problem 1:

$6 \frac{6}{7} + 5 \frac{1}{3} + 6 \frac{1}{7} + 7 \frac{2}{32}$

First, let's convert all the mixed numbers into improper fractions:

$6 \frac{6}{7} = \frac{6 \times 7}{7} + \frac{6}{7} = \frac{42}{7} + \frac{6}{7} = \frac{48}{7}$

$5 \frac{1}{3} = \frac{5 \times 3}{3} + \frac{1}{3} = \frac{15}{3} + \frac{1}{3} = \frac{16}{3}$

$6 \frac{1}{7} = \frac{6 \times 7}{7} + \frac{1}{7} = \frac{42}{7} + \frac{1}{7} = \frac{43}{7}$

$7 \frac{2}{32} = \frac{7 \times 32}{32} + \frac{2}{32} = \frac{224}{32} + \frac{2}{32} = \frac{226}{32}$

Now, add these fractions:

$\frac{48}{7} + \frac{16}{3} + \frac{43}{7} + \frac{226}{32}$

To add these fractions, find a common denominator, which in this case is 224 (the least common multiple of 7, 3, and 32).

$\frac{48 \times 32}{7 \times 32} + \frac{16 \times 224}{3 \times 224} + \frac{43 \times 32}{7 \times 32} + \frac{226 \times 7}{32 \times 7}$

$\frac{1536}{224} + \frac{3584}{224} + \frac{1376}{224} + \frac{1582}{224}$

Now add the numerators:

$\frac{1536 + 3584 + 1376 + 1582}{224}$

$= \frac{8080}{224}$

$= \frac{4040}{112}$

$= 36 \frac{8}{112}$

Simplified, this is $36 \frac{1}{14}$.

Problem 2:

$5 \frac{7}{10} + 7 \frac{12}{19} + 8 \frac{3}{10} + 100 \frac{7}{19}$