Question

4)х-3у-6=05)4х-у-3=06)-х+2у-5=0​

Answer 1

Но ведь там нужно строить графики?

Answer 2

Ответ:

1)х=6 2)Х+4 3)х=2

Пошаговое объяснение:

Answer 3

It looks like you have a system of three linear equations with two variables, x and y. You can solve this system of equations using various methods, such as substitution, elimination, or matrix algebra. I'll use the elimination method to solve this system.

Here are the equations:

1. x - 3y - 6 = 0
2. 4x - y - 3 = 0
3. -x + 2y - 5 = 0

First, let's isolate one of the variables in terms of the other two equations. We can use Equation 2 to isolate y:

From Equation 2: 4x - y - 3 = 0 4x - 3 = y

Now, we can substitute this expression for y into the other two equations:

1. x - 3(4x - 3) - 6 = 0
2. -x + 2(4x - 3) - 5 = 0

Now, we can solve this simplified system of equations:

1. x - 12x + 9 - 6 = 0
2. -x + 8x - 6 - 5 = 0

Simplify further:

1. -11x + 3 = 0
2. 7x - 11 = 0

Now, solve for x:

1. -11x = -3
2. 7x = 11

For Equation 1:

x = -3/(-11) x = 3/11

For Equation 2:

x = 11/7

Now that we have found the values of x, we can find the values of y using the expression we found earlier for y:

y = 4x - 3

For x = 3/11:

y = 4(3/11) - 3 y = 12/11 - 3 y = (12/11) - (33/11) y = (12 - 33)/11 y = -21/11

For x = 11/7:

y = 4(11/7) - 3 y = 44/7 - 3 y = (44/7) - (21/7) y = (44 - 21)/7 y = 23/7

So, the solution to the system of equations is:

For x = 3/11 and y = -21/11 OR For x = 11/7 and y = 23/7