Question

5x²+16x-10=0x1+x2-?​

Answer 1

Ответ:

$\frac{16}{5}$

Пошаговое объяснение:

Делим уравнение на 5

х²+$\frac{16}{5}$-2=0

х1+х1=-$\frac{16}{5}$

Answer 2

Ответ:

5x²+16x-10=0

По т. Виета:

x1 + x2 = -b/a = -16/5 = - 3,2

Answer 3

It looks like you're trying to find the values of x for the equation 5x² + 16x - 10 = 0. To do this, you can use the quadratic formula, which is given as:

x = (-b ± √(b² - 4ac)) / (2a)

In your equation, a = 5, b = 16, and c = -10. Plug these values into the quadratic formula:

x = (-16 ± √(16² - 4 * 5 * (-10))) / (2 * 5)

x = (-16 ± √(256 + 200)) / 10

x = (-16 ± √456) / 10

Now, you can simplify the square root:

x = (-16 ± √(4 * 114)) / 10

x = (-16 ± 2√114) / 10

Now, you can simplify further by dividing both the numerator and denominator by 2:

x = (-8 ± √114) / 5

So, the two solutions for x are:

1. x = (-8 + √114) / 5
2. x = (-8 - √114) / 5

Answer 4

It looks like you want to find the solution to the quadratic equation $5x^2 + 16x - 10 = 0$. To do this, you can use the quadratic formula, which is:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation, $a = 5$, $b = 16$, and $c = -10$. Plug these values into the quadratic formula:

$x = \frac{-16 \pm \sqrt{16^2 - 4 \cdot 5 \cdot (-10)}}{2 \cdot 5}$

Now, calculate the values:

$x = \frac{-16 \pm \sqrt{256 + 200}}{10}$

$x = \frac{-16 \pm \sqrt{456}}{10}$

Now, find the square root of 456:

$x = \frac{-16 \pm 2\sqrt{114}}{10}$

You can simplify this further by dividing both the numerator and denominator by 2:

$x = \frac{-8 \pm \sqrt{114}}{5}$

So, the solutions for $x$ are:

$x_1 = \frac{-8 + \sqrt{114}}{5}$

$x_2 = \frac{-8 - \sqrt{114}}{5}$

These are the two solutions to the quadratic equation $5x^2 + 16x - 10 = 0$.