Question

X(x-4)-(x+3)(x-5) >-5​

Answer 1

Ответ:

${x}^{2} - 4x - {x}^{2} + 5x - 3x = - 15 - 5 \\ - 2x = - 20 \\ x = 10$

Answer 2

To solve the inequality $X(x-4)-(x+3)(x-5) > -5,$ we need to expand and simplify the expression on the left-hand side and then solve the resulting quadratic inequality.

First, let's expand the left-hand side:

$X(x-4) - (x+3)(x-5) > -5$

Expand the second term on the left-hand side:

$X(x) - X(4) - (x^2 - 5x + 3x - 15) > -5$

Simplify further:

$Xx - 4X - x^2 - 2x + 15 > -5$

Now, rearrange the terms to form a quadratic inequality:

$-x^2 + (X-2)x + (15-4X) + 5 > 0$

Now, you have a quadratic inequality in the form of $ax^2 + bx + c > 0$, where $a = -1$, $b = X-2$, and $c = 20-4X$. To solve this inequality, you can use various methods, such as factoring or the quadratic formula. However, the solution will depend on the specific value of $X$ you are considering. If you have a specific value of $X$ in mind, please provide it, and I can help you solve the inequality accordingly.