Question

7(х+2)=-14 2(3х-4)=4(х-3) 5+3(2у-1)=2(у-3)

Answer 1

7(x+2)=-14

7х+14=-14

7х+14-14=-14-14

7х=-28

х=-4

2(3х-4)=4(х-3)

6х-8=4(х-3)

6х-8=4х-12

6х-8+8=4х-12+8

6х=4х-4

6х-4х=4х-4-4х

2х=-4

х=-2

Answer 2

Let's solve each of these equations step by step:

1. $7(x+2) = -14$

First, distribute the 7 on the left side of the equation:

$7x + 14 = -14$

Now, subtract 14 from both sides of the equation to isolate $7x$:

$7x = -14 - 14$

$7x = -28$

To solve for $x$, divide both sides by 7:

$x = -28 / 7$

$x = -4$

So, the solution is $x = -4$.

2. $2(3x-4) = 4(x-3)$

First, distribute the constants on both sides of the equation:

$6x - 8 = 4x - 12$

Next, move all the $x$ terms to one side of the equation by subtracting 4x from both sides:

$6x - 4x - 8 = -12$

Combine like terms on the left side:

$2x - 8 = -12$

Now, add 8 to both sides to isolate $2x$:

$2x - 8 + 8 = -12 + 8$

$2x = -4$

Finally, divide both sides by 2 to solve for $x$:

$2x / 2 = -4 / 2$

$x = -2$

So, the solution is $x = -2$.

3. $5 + 3(2y-1) = 2(y-3)$

First, distribute the constants and the coefficients on both sides:

$5 + 6y - 3 = 2y - 6$

Now, combine like terms on both sides of the equation:

$6y + 2y - 5 + 3 = -6$

$8y - 2 = -6$

Next, add 2 to both sides to isolate $8y$:

$8y - 2 + 2 = -6 + 2$

$8y = -4$

Finally, divide both sides by 8 to solve for (y:

$8y / 8 = -4 / 8$

$y = -1/2$

So, the solution is $y = -1/2$.