Question

(5 1/39-4 7/26-1/6)*(3/4-2/3+5/6)=​

Answer 1

Ответ:

ответ :0.54059829059

Пошаговое объяснение:

вроде правильно

Answer 2

Let's break down the expression step by step:

$(5 \frac{1}{39} - 4 \frac{7}{26} - \frac{1}{6}) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

First, convert the mixed numbers to improper fractions:

$( \frac{5 \cdot 39 + 1}{39} - \frac{4 \cdot 26 + 7}{26} - \frac{1}{6} ) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

Simplify the fractions:

$( \frac{196 + 1}{39} - \frac{104 + 7}{26} - \frac{1}{6} ) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

$( \frac{197}{39} - \frac{111}{26} - \frac{1}{6} ) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

Now, find a common denominator for the terms in the parentheses. The common denominator is 12:

$( \frac{197}{39} - \frac{429}{78} - \frac{13}{78} ) \times \left(\frac{9}{12} - \frac{8}{12} + \frac{10}{12}\right)$

Combine like terms:

$( \frac{197}{39} - \frac{442}{78} ) \times \left(\frac{11}{12}\right)$

Now, find a common denominator for the terms in the parentheses. The common denominator is 78:

$( \frac{197}{39} - \frac{442}{78} ) \times \left(\frac{429}{468}\right)$

Combine like terms:

$\frac{197 \cdot 78 - 442 \cdot 39}{39 \cdot 78} \times \frac{429}{468}$

Perform the multiplication and simplify:

$\frac{15366 - 17238}{3042} \times \frac{429}{468}$

$\frac{-1872}{3042} \times \frac{429}{468}$

$\frac{-1872}{3042} \times \frac{143}{156}$

$\frac{-267264}{474312}$

Simplify the fraction:

$\frac{-4421}{7839}$

So, $(5 \frac{1}{39} - 4 \frac{7}{26} - \frac{1}{6}) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right) = \frac{-4421}{7839}$

Answer 3

Let's break down the expression step by step:

$(5 \frac{1}{39} - 4 \frac{7}{26} - \frac{1}{6}) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

First, let's simplify the terms inside the parentheses:

$5 \frac{1}{39} = \frac{5 \times 39 + 1}{39} = \frac{195 + 1}{39} = \frac{196}{39}$

$4 \frac{7}{26} = \frac{4 \times 26 + 7}{26} = \frac{104 + 7}{26} = \frac{111}{26}$

Now the expression becomes:

$\left(\frac{196}{39} - \frac{111}{26} - \frac{1}{6}\right) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right)$

Now find a common denominator for the fractions in each set of parentheses. The common denominator for 39, 26, and 6 is 78.

$\left(\frac{196 \times 2}{39 \times 2} - \frac{111 \times 3}{26 \times 3} - \frac{1 \times 13}{6 \times 13}\right) \times \left(\frac{3 \times 13}{4 \times 13} - \frac{2 \times 26}{3 \times 26} + \frac{5 \times 13}{6 \times 13}\right)$

This simplifies to:

$\left(\frac{392}{78} - \frac{333}{78} - \frac{13}{78}\right) \times \left(\frac{39}{52} - \frac{52}{78} + \frac{65}{78}\right)$

Combine the terms in each set of parentheses:

$\left(\frac{392 - 333 - 13}{78}\right) \times \left(\frac{39 - 52 + 65}{78}\right)$

Simplify further:

$\left(\frac{46}{78}\right) \times \left(\frac{52}{78}\right)$

Now multiply the fractions:

$\frac{46 \times 52}{78 \times 78}$

$\frac{2392}{6084}$

This fraction can be simplified by dividing both the numerator and denominator by their greatest common factor, which is 4:

$\frac{598}{1521}$

Therefore, $(5 \frac{1}{39} - 4 \frac{7}{26} - \frac{1}{6}) \times \left(\frac{3}{4} - \frac{2}{3} + \frac{5}{6}\right) = \frac{598}{1521}$.