Question

(a-1) (a+3) - (a+1)^2

Answer 1

Ответ:

Пошаговое объяснение:

a²+3a-1a-3-(a²+2a+1)=a²+3a-a-3-a²-2a-1=a-4

Answer 2

(a-1)(a+3)-(a+1)^2=a^2+3a-a-3-(a^2+2a+1)=a^2+3a-a-3-a^2-2a-1=0-4=-4
ответ: -4

Answer 3

To simplify the expression $(a-1)(a+3) - (a+1)^2$, you can expand and simplify each part step by step. Here's how to do it:

1. Expand the first part $(a-1)(a+3)$:

   $(a-1)(a+3) = a(a+3) - 1(a+3) = a^2 + 3a - a - 3$

2. Combine like terms:

   $a^2 + 2a - 3$

3. Now, expand the second part $(a+1)^2$:

   $(a+1)^2 = (a+1)(a+1) = a(a+1) + 1(a+1) = a^2 + a + a + 1$

4. Combine like terms:

   $a^2 + 2a + 1$

Now, subtract the second expression from the first:

$(a^2 + 2a - 3) - (a^2 + 2a + 1)$

When you subtract, distribute the negative sign to each term inside the parentheses:

$a^2 + 2a - 3 - a^2 - 2a - 1$

Now, combine like terms:

$(a^2 - a^2) + (2a - 2a) + (-3 - 1)$

The first two terms cancel each other out, and the third term is simplified:

$0 + 0 - 4 = -4$

So, the simplified expression is $-4$.